A light with an electric field `E = 165 [sin (22 xx 10^(15)t) + sin(pi lt 10^(14)t) Vm^(-1)` where t is in seconds, falls on a metal of work function 2 eV. The maximum kinetic energy of the photoelectron is `(h=4.14 xx 10^(15)eV.S)`

Options

A. 1.8eV
B. 2.14eV
C. 2.34eV
D. 4.41eV

Answer

B

Explanation

Maximum K.E. of photoelectron,
`E_(k)=hv-W, " where work function W=2eV"`
`E_(k)=4.41 xx 10^(-15) 10^(15)-2=2.14eV`