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The flux of a alpha-particle at 2^@ is 1...

The flux of a `alpha`-particle at `2^@` is 1 x 10°, calculate the flux of `alpha-` particle at angle `60^(@)`.

A

0.5

B

0.75

C

1.5

D

1.2

Text Solution

Verified by Experts

The correct Answer is:
C
`N_(phi) alpha (1)/(sin^(4) ""theta/2)`
`(N_(60))/(N_(2))=(sin^(4) 1^(@))/(sin^(4) 30^(@))=1.50 xx 10^(-6)`
`N_(60)=N_(2) xx 1.5 xx 10^(-6)`
`N_(60)=1.5`
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