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The binding energy per nucleon for deute...

The binding energy per nucleon for deuteron `(""_(1)^(2)H)" helium "(""_(2)^(4)He)` are 1.1MeV and 7.0 MeV. The energy released when deuterons fuse to form a helium nucleus is:

A

2.3 MeV

B

23.6MeV

C

28.0MeV

D

30.2MeV

Text Solution

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The correct Answer is:
C
B.E. of `4/2 He=7 xx 4=28.0MeV`
`B.E. of ""_(1)^(2)H=1.1 xx 2=2.2 MeV`
Energy Released `=29.0-(2 xx 2.2) =23.6 MeV`
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