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The radius of ""(29)Cu^(64) nucleus in F...

The radius of `""_(29)Cu^(64)` nucleus in Fermi is : `("given "R_(0)=1.2 xx 10^(-15)m)`

A

9.6

B

4.8

C

1.2

D

7.7

Text Solution

Verified by Experts

The correct Answer is:
B
`R=R_(0) A^(1//3) =1.2 xx 10^(-15) xx (64)^(1//3)`
`=4.8 xx 10^(-15) m`
`=4.8" fermi"`
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