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The diameter of a brass rod is 4 mm and ...

The diameter of a brass rod is 4 mm and Young's modulus of brass is `9xx10^(10)" N"//"m"^(2)`. The force required to stretch by `0.1%` of its length is :

A

36 N

B

`144pi xx 10^(3)N`

C

`360 pi N`

D

`36 pi xx10^(5)` N.

Text Solution

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The correct Answer is:
C
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