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Let a(n)=(1000^(n))/(n!) for n in N. The...

Let `a_(n)=(1000^(n))/(n!)` for `n in N`. Then `a_(n)` is greatest when:

A

n=997

B

n=998

C

n=999

D

n=996

Text Solution

Verified by Experts

The correct Answer is:
C
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