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underset("n-digits")((666"……"6))^(2) +un...

`underset("n-digits")((666"……"6))^(2) +underset("n-digits") (( 888"…" 8 ))` is equal to `:`

A

`(4)/( 9) ( 10^(n) -1)`

B

`( 4)/( 9)( 10^(2n) - 1)`

C

`(4)/(9) ( 10^(n) -1)^(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
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