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If sum(r=1)^(n) t(r ) = sum(k=1)^(n) sum...

If `sum_(r=1)^(n) t_(r ) = sum_(k=1)^(n) sum_(j=1)^(k) sum_(i=1)^(j) 2`, then `sum_(r=1)^(n) (1)/( t_(r ))` equals `:`

A

`(n+1)/( n )`

B

`( n )/( n + 1)`

C

`(n-1)/( n ) `

D

`( n )/(n-1)`

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The correct Answer is:
B
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