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Let Delta=|(a,a+b,a+b+c),(3a,4a+3b,5a+4b...

Let `Delta=|(a,a+b,a+b+c),(3a,4a+3b,5a+4b+3c),(6a,9a+6b,11a+9b+6c)|` where `a=i, b=omega,c = omega^2` , then `Delta` is equal to

A

i

B

`-omega^2`

C

`omega`

D

`-i`

Text Solution

Verified by Experts

The correct Answer is:
A
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