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Let omega=-(1)/(2)+i (sqrt(3))/(2), then...

Let `omega=-(1)/(2)+i (sqrt(3))/(2)`, then the value of
`[[1,1,1],[1,-1-omega^(2),omega^(2)],[1,omega^(2),omega^(4)]]` is

A

`3omega`

B

`3omega(omega-1)`

C

`3omega^2`

D

`3omega(1-omega)`

Text Solution

Verified by Experts

The correct Answer is:
B
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