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If sin2x=1 , then |(0,cosx,-sinx),(sinx...

If `sin2x=1 , ` then `|(0,cosx,-sinx),(sinx,0,cosx),(cosx,sinx,0)|` equals :

A

1

B

2

C

3

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • int (sinx-cosx)/(cosx+sinx)dx =

    A
    1/(sinx + cos x)+C
    B
    -log (sinx +cos x)+C
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    D
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  • If, x,y inR , then the determinant: Delta=|(cosx,-sinx,1),(sinx,cosx,1),(cos(x+y),-sin(x+y),0)| lies in the interval .

    A
    `[-sqrt2,sqrt2]`
    B
    `[-1,1]`
    C
    `[-sqrt2,sqrt2]`
    D
    `[-1,-sqrt2]`
  • int (2sinx-cosx)/(2cosx+sinx)dx =

    A
    -log (sinx +2cos x)+C
    B
    1/2 log (sin x+2cos x)+C
    C
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