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The value of int1^2 [f{g (x)}]^(-1) . f'...

The value of `int_1^2 [f{g (x)}]^(-1) . f'{g(x)} cdot g' (x)dx`, where `g(1) = g(2)`, is equal to :

A

0

B

1

C

2

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
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