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Solution of ZnS in dil HCl , when treate...

Solution of ZnS in dil HCl , when treated with NaOH solution , a white ppt. is formed which dissolves in excess of NaOH due to the formation of :

A

`Zn(OH)_2`

B

`Zn(OH)Cl`

C

`Na_2ZnO_2`

D

`Na_2ZnO_3`.

Text Solution

Verified by Experts

The correct Answer is:
C
`ZnS + 2HCl to ZnCl_2 + H_2S `
`ZnCl_2 + 2NaOH to Zn(OH)_2 + 2NaCl`
`Zn(OH)_2 + underset("excess")(2NaOH) to underset("Sod zincate (soluble)")+ 2H_2O`
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