The heat of neutralisation of HCl and NaOH is 57.3 kJ `"mol"^(-1)`. The amount of heat liberated when 0.25 mol of HCl reacts with 1 mol of NaOH is :

Options

A. 57.3 kJ
B. 14.325 kJ
C. 28.65kJ
D. 114.6 kJ

Answer

C

Explanation

Heat liberated for neutralisation of 0.5 mol of `H^(+) = 57.3 xx 0.5 = 28.65 kJ`