During the fission of U-235, a large amount of energy of the order of 180 MeV is generated per nucleus fissioned. The amount of energy released by the fission of 0.235 g of U-235 is :

Options

A. `6.932xx10^(23)kJ`
B. `1.08xx10^(7)kJ`
C. `1.73xx10^(16)kJ`
D. `1.73xx10^(7)kJ`

Answer

D

Explanation

No. of nuclei in 0.235 g of U-235
`=(6.02xx10^(23)xx0.235)/(235)`
`=6.02xx10^(20)` Amount of energy released
`=6=02xx10^(20)xx180MeV`
`=6.02xx10^(20)xx180xx1.6xx10^(-16)kJ`
`=1.73xx10^(7)kJ`