Home
Class 12
CHEMISTRY
(3.50 xx 10^2 mL) – (0.0225 L) may be w...

` (3.50 xx 10^2 mL) – (0.0225 L)` may be written to correct significant digits :

Text Solution

Verified by Experts

The correct Answer is:
A

`{:(3.50 xx 10^2 mL),(-0.225 xx 10^2 mL),(overline(3.275 xx 10^2 mL )):}`
` = 3.28 xx 10^2 mL`
(upto two decimal places as in 0.50 )
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTION (LEVEL-II)|100 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTION (LEVEL-III)|5 Videos
  • SOLUTIONS

    MODERN PUBLICATION|Exercise Recent Examination Questions|13 Videos
  • STATES OF MATTER

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTIONS|12 Videos

Similar Questions

Explore conceptually related problems

Add 4.00 xx 10^(-2) , 3.26 xx 10^(-3) and 1 xx 10^(-6) to the correct number of significant digits :

The decimal equivalent of 2/5 may be written upto four significant figures as :

The height of a boy who is 5 feet and 9 inches may be written with three significant figures as (1 inch = 2.54 cm)

In the final answer of the expression ((29.2 -20.2)(1.79 xx 10^5))/(1.37) the number of significant figures is :

The mass of a piece of paper is 0.02 g and the mass of a solid substance and the piece of paper is 20.036 g. If the volume of the solid is 2.16 cm^3 , calculate its density to the proper number of significant digits.

How many different numbers which are smaller than 2xx10^(8) and are divisible by 3, can be written by means of the digits 0,1 and 2?

The result of (2.36 xx 0.07251)/(2.103) will contain the significant figures equal to

The rate for a first order reaction is 0.6932 xx 10^(-2) mol " "L^(-1) and the initial concentration of the reactant is 1M, t_(1//2) is equal to

Find the numbers of zeroes between the decimal point and first significant digit of (0.036)^16 , where log 2=0.301 and log 3=0.477 .

The putial pressure of ethane over a saturated solution containing 6.56 xx 10^(-2) g of ethane is 1 bar.if the solution contains 5.0 xx 10^(-2) g of ethane, then what will be the partial pressure of the gas ?