Home
Class 12
CHEMISTRY
A sample of CaCO3 has Ca = 40%, C = 12%...

A sample of `CaCO_3` has Ca = 40%, C = 12% and O = 48%. If the law of constant proportion is true then the weight of calcium in 5 g of a sample of `CaCO_3` from another source will be

A

0.20 g

B

2.0 g

C

2.5 g

D

4.0 g

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTION (LEVEL-II)|100 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTION (LEVEL-III)|5 Videos

  • SOLUTIONS

    MODERN PUBLICATION|Exercise Recent Examination Questions|13 Videos

  • STATES OF MATTER

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTIONS|12 Videos

Similar Questions

Explore conceptually related problems

If the law of constant compositon is true, what weights of calcium carbon, and oxygen are present in 1.5 g of calcium carbonate, if a sample of calcium carbonate from another source contains the following percentage composition: Ca = 40.0%, C = 12.0% , and O = 48.0% ?

A mixture of FeO and Fe_(3)O_(4) when heated in air to a constant weight, gains 5% of its weight. Find the composition of the intial mixutre.

For the equilibrium: CaCO_(3(s)) iff CaO_((s)) + CO_(2(g)) , K_p = 1.64 atm at 1000 K, 50 g of CaCO_3 in a 10 litre closed vessel is heated to 1000 K. Percentage of ĆaCO_3 that remains unreacted at equilibrium is (Given R=0.082 L atm K^(-1) "mol"^(-1) ).

PA and PB are two tangents drawn from point P to circle of radius 5 . A line is drawn from point P which cuts at C and D such that PC=5 and PD=15 and angleAPB= theta . On the basis of above information answer the questions . Number of solution(s) of the equation log_(cos theta )(x+2)=2+3 log_((x+2)) sin""((5 theta )/(2)) is

A mixture of CaCO_(3) and MgCO_(3) weighing 1.84 g on heating left a residue weighing 0.96 g . Calculate the percentage of each in the mixture.