How many moles of NaOH are present in 27mL of 0.015 M NaOH ?

Options

A. `4.05 xx 10^(-3)`
B. `4.05 xx 10^(-4)`
C. `4.05 `
D. `0.0405 `

Answer

B

Explanation

Moles of `NaOH = (0.015)/(1000) xx 27 ml `
` = 4.05 xx 10^(-4) ` mol