1.0 g of an oxide of metal M contained 0.5 g of M and 4.0 g of another oxide of M contained 1.6 g of M. These data illustrate the

Options

A. Law of reciprocal proportion
B. Law of conservation of mass
C. Law of constant proportion
D. Law of multiple proportion

Answer

D

Explanation

1.0 g of an oxide contained 0.5 g of metal M.
Mass of oxygen = 1.0 - 0.5 = 0.5 g
Mass of oxygen which combines with 0.5 g of metal = 0.5 g
Mass of oxygen in second oxide = 4.0 - 1.6 = 2.4 g
Mass of oxygen which combines with 1.6 g of metal = 2.4 g
Mass of oxygen which combines with 0.5 g of metal ` = (2.4)/(1.6) xx 0.5 = 0.75 g `
Ratio of different masses of oxygen combining with 0.5 g of metal
0.5 : 0.75
2 : 3
sicne it is simple ratio ,it illustrates law of multiple proportions .