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A given sample of AlCl3 contains 6.02 ...

A given sample of `AlCl_3` contains `6.02 xx 10^20 Al^(3+)` ions. The moles of `Cl^(-1)` ions are :

A

`1.0 xx 10^(-3)`

B

`3.0 xx 10^(-3)`

C

`3.0 xx 10^3`

D

`0.33 xx 10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
B
No. of `Cl^(-)` ions = ` 3 xx 6.02 xx 10^20`
Moles of `Cl^(-)` ions
` = (3 xx 6.02 xx 10^20)/(6.02 xx 10^23) = 3 xx 10^(-3)`
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