What weight of `CO_(2)` will contain same number of oxygen atoms as are present in 3.6 g of water ?

Options

A. 8.8 g
B. 7.2 g
C. 4.4 g
D. 220 g

Answer

C

Explanation

No. of water molecules in 3.6 g of water
` = (3.6)/(18) xx 6 xx 10^23 ` molecules
` = 1.2 xx 10^23 ` molecules
No. of oxygen atoms
` = 1.2 xx 10^23`
Now ` 2 xx 6 xx 10^23` atoms of oxygen in `CO_2`
= 44g
`1.2 xx 10^23` atoms of oxygen in `CO_2`
` = (44)/(2 xx 6 xx 10^23) xx 1.2 xx 10^23`
4.4 g