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The volume of SO2 produced at S.T.P. by...

The volume of `SO_2` produced at S.T.P. by the combustion of 50 g of sulphur containing 4% sand by weight will be

A

33.6 L

B

22.4L

C

11.2 L

D

44.8 L

Text Solution

Verified by Experts

The correct Answer is:
A
Amount of sand ` = (50 xx 4)/(100) = 2g`
Amount of sulphur = 50 - 2 = 48 g
`underset(32g)(S) + O_2 to underset(22.4L)(SO_2)`
32g of sulphur at S.T.P. give `SO_2` = 22.4 L
48 g of sulphur at S.T.P. Give `SO_2`
` = (22.4)/(32) xx 48 = 33.6`
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