What is the number of potassium atoms required to prepare 1 equivalent of `KMnO_4` ?

Options

A. `6.02 xx 10^23`
B. `3.01 xx 10^24`
C. `1.204 xx 10^23`
D. `1`

Answer

C

Explanation

1 equivalentof `KMnO_4 = 1/5` mole of `KMnO_4`
`1/5` mole of `KMnO_4 = 1/5 ` mole of K atoms
` =(6.02 xx 10^23)/(5) = 1.204 xx 10^23 ` atoms