If 22.4 ml of a triatomic gas has a mass of 0.048 g at 273K and 1 atm pressure, then the mass of one atom is:

Options

A. `7.9 xx 10^(-23) g `
B. `2.6 xx 10^(-23) g `
C. `2.4 xx 10^(-22) g `
D. `2.4 xx 10^(-23) g `

Answer

B

Explanation

22400 ml of gas weight
` = (0.048)/(22.4) xx 22400 = 48 g `
` therefore ` 1 mol of gas = 48 g
Mass of one atom
`= (48)/(3 xx 6.02 xx 10^23) = 2.6 xx 10^(-23) g `