Common salt obtained from sea water contains 95% NaCl by mass. The approximate number of molecules present in 10g of the salt is

Options

A. `10^21`
B. `10^22`
C. `10^23`
D. `10^24`

Answer

C

Explanation

Number of molecules in 10 g of NaCl having 95% purity
` = (6.023 xx 10^23)/(58.5) xx 10 xx 95/100`
`= 9.78 xx 10^22 = 10^23`