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The molarity of 98% H2SO4 (d = 1.8 g/mL...

The molarity of 98% `H_2SO_4` (d = 1.8 g/mL) by weight is

A

6M

B

18M

C

10M

D

4M

Text Solution

Verified by Experts

The correct Answer is:
B
98% `H_2SO_4` means 98 g `H_2SO_4` is present in 100 g of solution
volume of 100 g solution
`= (100)/(1.8) = 55.55 mL `
molarity ` =("moles of " H_2SO_4 xx 1000 )/("volume of solution")`
`= (98)/(98 xx 55.55) xx 1000 = 18 M`
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