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The volume of 0.1 M Ca(OH)2 required t...

The volume of 0.1 M `Ca(OH)_2` required to neutralize 10 mL of 0.1 N HCI

A

10 mL

B

20 mL

C

5mL

D

15mL

Text Solution

Verified by Experts

The correct Answer is:
C
`0.1 M Ca(OH)_2 = 0.2 N Ca (OH)_2`
Applying `N_1V_1 = N_2V_2`
`0.2 xx V_1 = 0.1 xx 10`
` V_1 = (0.1 xx 10)/(0.2) =5mL`
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