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The volume of 0.1 M oxalic acid that can...

The volume of 0.1 M oxalic acid that can be completely oxidized by 20 mL of 0.025 M `KMnO_4` solution is

A

125mL

B

25mL

C

12.5mL

D

37.5 mL

Text Solution

Verified by Experts

The correct Answer is:
C
`5H_2C_2O_4 + 2KMnO_4 + 3H_2SO_4 to 2MnSO_4 + K_2SO_4 + 10CO_2 + 8H_2O`
According to molarity equation
` ( (M_1V_1)/(n_1) )_(KMnO_4) = ( (M_2V_2)/(n_2) )_("oxalic acid")`
or ` (0.025 xx 20)/(2) = (0.1 xx V_2)/(5) `
`V_2 = (5 xx 0.025 xx 20)/(2 xx 0.1)`
` = 12.5 mL`
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