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The number of water molecules present in...

The number of water molecules present in a drop of water weighing 0.18g is :

A

`6.022 xx 10^26`

B

`6.022 xx 10^23`

C

`6.022 xx 10^19`

D

`6.022 xx 10^21`

Text Solution

Verified by Experts

The correct Answer is:
D

Moles of water in a drop
` = (0.018)/(18) = 1 xx 10^(-3) ` moles
1 mol of water ` = 6.022 xx 10^23` molecules
` 1 xx 10^(-3) ` mole of water
` = 6.022 xx 10^23 xx 1 xx 10^(-3)`
` = 6.022 xx 10^20` molecules
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