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The enthalpies of formation of N(2)O and...

The enthalpies of formation of `N_(2)O` and NO at 298 K are 82 and 90 `kJ mol^(-1)`. The enthalpy of the reaction :
`N_(2)O(g) + (1)/(2) O_(2) rarr 2 NO(g)` is

A

`-8 kJ`

B

98 kJ

C

`-74 kJ`

D

8 kJ

Text Solution

Verified by Experts

The correct Answer is:
B
(i) `N_(2) + ½O_(2) rarr N_(2)O, Delta H = 82 kJ`
(ii) `½N_(2) + ½O_(2) rarr NO, Delta H = 90 kJ`
`N_(2)O + ½O_(2) rarr 2NO, Delta H = ?`
Multiplying (ii) by 2 and subtract (i) from it
`N_(2)O + (1)/(2)O_(2) rarr 2NO, Delta H = (90 xx 2) = 98 kJ`
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