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For the reaction, 2H(2)O(g) rarr 2H(2)...

For the reaction,
`2H_(2)O(g) rarr 2H_(2)(g) + O_(2)(g), Delta H = 571.6 kJ`
`Delta_(f) H^(theta)` of water is:

A

285.8kJ

B

`-285.8kJ`

C

1143.2kJ

D

`-1143.2kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta_(f) H (H_(2)O)` may be written as
`H_(2)(g) + (1)/(2) O_(2)(g) rarr H_(2)O(g)`
`Delta_(f)H (H_(2)O) = - 571.6/2 = - 285.8 kJ`
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