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Delta H for the reaction, SO(2) (g) + ...

`Delta H` for the reaction,
`SO_(2) (g) + (1)/(2) O_(2)(g) hArr SO_(3)(g) " " Delta H = -98.3kJ`
If the enthalpy of formation of `SO_(3)(g)` is -395.4kJ, then enthalpy of formation of `SO_(2)(g)` is:

A

`-297.1kJ`

B

`493.7kJ`

C

`-493.7kJ`

D

`297.1kJ`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta H = Delta_(f) H(SO_(3)) - [Delta_(f) H(SO_(2)) + (1)/(2) Delta_(f) H(O_(2))]`
`-98.3 = -395.4 - [Delta_(f) H(SO_(2)) + 0]`
or `Delta_(f)H(SO_(2)) = -395.4 + 98.3 = -297.1 kJ`
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