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The enthalpy of the reaction : H(2)O(2...

The enthalpy of the reaction :
`H_(2)O_(2)(l) rarr H_(2)O(l) + (1)/(2)O_(2)(g)`
is `-98.3 KJ mol^(-1)` and the enthalpy of formation of `H_(2)O(l)` is `-285.6 kJ mol^(-1)`. The enthalpy of formation of `H_(2)O_(2)(l)` is :

A

`-187.3 kJ`

B

187.3 kJ

C

`-383.9 kJ`

D

383.9 kJ

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta H = Delta H_(f) (H_(2)O) + (1)/(2) Delta H_(f) (O_(2)) - Delta H_(f) (H_(2)O_(2))`
`- 98.3 = -285.6 + 0 - Delta H_(f)(H_(2)O_(2))`
`Delta H_(f)(H_(2)O_(2)) = +98.3 - 285.6`
`= -187.3 kcal`
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