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H(2) + (1)/(2) O(2) rarr H(2)O, Delta = ...

`H_(2) + (1)/(2) O_(2) rarr H_(2)O, Delta = -68.39 kcal`
`K + H_(2)O rarr KOH + (1)/(2) H_(2), Delta H = -48 kcal`
`KOH + Water rarr KOH (aq), Delta H = -14 kcal`
The heat of formation of KOH in kcal is :

A

`-34.39 kcal`

B

102.39 kcal

C

34.39 kcal

D

130.39 kcal

Text Solution

Verified by Experts

The correct Answer is:
B
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