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Given that C + O(2) rarr CO(2) Delta H...

Given that
`C + O_(2) rarr CO_(2) Delta H^(theta) = -x kJ`
`2CO + O_(2) rarr 2CO_(2) Delta H^(theta) = - y kJ`
The enthalpy of formation of CO is :

A

`(y - 2x)/(2)`

B

y - 2x

C

2x - y

D

`(x - y)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`C + (1)/(2) O_(2) rarr CO`
:. `Delta H(CO) = Eq. (i) - (1)/(2) Eq. (ii)`
`Delta H = - x + y//2 = (y - 2x)/(2)`
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