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Calculate the heat of the reaction : C...

Calculate the heat of the reaction :
`CH_(2) = CH_(2)(g) + H_(2)(g) rarr CH_(3)CH_(3)(g)`
given that bond energy of C-C, C=C, C-H and H-H is 80, 145, 98 and 103 kcal.

A

`-28 kcal mol^(-1)`

B

`-5.6 kcal mol^(-1)`

C

`-2.8 kcal mol^(-1)`

D

`-56 kcal mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta H = B. E. (C = C) + 4 B. E. (C-H) + B. E. (H-H) - B. E. (C-C) - 6 B. E. (C-H)`
`= 145 + 4(98) + 103 - 80 - 6 (98)`
`= -28 kcal mol^(-1)`
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