Home
Class 12
CHEMISTRY
The standard free energy changes (Delta ...

The standard free energy changes `(Delta G^(theta))` is related to equilibrium constant (K) as

A

`Delta G^(theta) = -2.303 RT ln K`

B

`Delta G^(theta) = 2.303 RT log K`

C

`Delta G^(theta) = -2.303 RT log K`

D

`Delta G^(theta) = RT log K`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Multiple Choice Questions (Level-II)|85 Videos
  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Multiple Choice Questions (Level-III)|10 Videos
  • THE SOLID STATE

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTIONS|11 Videos
  • UNIT TEST - 3

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS|59 Videos

Similar Questions

Explore conceptually related problems

The standard free energy changes (Delta G^(@)) is related to equilibrium constant K_(p) as

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) , the standard free energy is Delta G^(@)gt 0 . The equilibrium constant (K) would be

The free energy change Delta G = 0 , when

Calculate the standard free energy change for a reaction at 273K, if the equilibrium constant of the reaction at 273K is 20

Calculate standard free energy change at 300K for a reaction whose equilibrium constant is 1 times 10^4 at 300K.

At equilibrium the free energy change (Delta G) is :

Write the relation between standard free energy change and equilibrium constant K_(p) for a reversible reaction.

Standard Gibb's energy change of a reaction is 62 kJ/mole. Calculate the equilibrium constant at 300 K.

Calculate the standard Gibb's energy change for a reaction at 298 K, if its equilibrium constant is 50.