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The enthalpy of vaporisation of a substa...

The enthalpy of vaporisation of a substance is `8400 J mol^(-1)` and its boiling point is ` -173^(@)C`. The entropy change for vaporisation is :

A

`84 J mol^(-1) K^(-1)`

B

`21 J mol^(-1) K^(-1)`

C

`49 J mol^(-1) K^(-1)`

D

`12 J mol^(-1) K^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta S = (Delta H)/(T_(b)) = (8400 J mol^(-1))/(100 K)`
`= 84 K mol^(-1) K^(-1)`
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