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If equilibrium constant K is 10^(3), the...

If equilibrium constant K is `10^(3)`, the `Delta G^(theta)` for the reaction at 300 K is (assume `R = 8.314 JK^(-1) mol^(-1)`) :

A

`- 16.582 kJ`

B

16.582 kJ

C

165.82 kJ

D

1658.2 kJ

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta G^(@) = -2.303 RT log K`
`= -2.303 x 8 xx 300 xx log 10^(3)`
`= -2.303 xx 8 xx 300 xx 3 = -16.582 kJ`
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