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The equilibrium constant for a reaction ...

The equilibrium constant for a reaction is 10. `Delta G^(theta)` will be `R = 8 JK^(-1) mol^(-1)`, T = 300 K)

A

`- 5527 kJ mol^(-1)`

B

`- 5.527 kJ mol^(-1)`

C

`- 55.27 kJ mol^(-1)`

D

`+ 5.527 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta G = -2.303 RT log K`
`= -2.303 xx 8 xx 300 xx log 10`
`= -2.303 xx 8 xx 300 = -5.527 kJ`
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