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If the enthalpy change for the transitio...

If the enthalpy change for the transition of liquid water to steam is 30 kJ mol^(-1) at `27^(@)C`, the entropy change for the process would be :

A

`10 J mol^(-1) K^(-1)`

B

`1.0 J mol^(-1) K^(-1)`

C

`0.1 mol^(-1) K^(-1)`

D

`100 J mol^(-1) K^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
Liquid water `rarr` Steam
`Delta S = (Delta H_("vap"))/(T) = (30 xx 10^(3) J mol^(-1))/(300 K)`
`= 100 J mol^(-1) K^(-1)`
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