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The amount of heat evolved when 500 cm^(...

The amount of heat evolved when `500 cm^(3)` of 0.1 M HCl is mixed with `200 cm^(3)` of 0.2 M NaOH is ……….

A

2.292 kJ

B

1.292 kJ

C

0.292 kJ

D

3.392 kJ

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(underset(0.1 M)(500 cm^(3)))(HCl) + underset(underset(0.2 M)(200 cm^(3)))NaOH rarr NaCl + H_(2)O`
Moles of HCl `= (0.1)/(1000) xx 500 = 0.05 moles`
Moles of NaOH `= (0.2)/(1000) xx 200 = 0.04 moles`
Moles of `H_(2)O` formed = 0.04 moles.
Heat released when 1 mol `H_(2)O` is formed = 57.3 kJ
Heat released when 0.04 mol `H_(2)O` is fromed
`= 0.04 xx 57.3 = 2.292 kJ`
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