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The spin only magnetic moment of Mn^(4+)...

The spin only magnetic moment of `Mn^(4+)` ion is nearly

A

3BM

B

6 BM

C

4 BM

D

5 BM

Text Solution

Verified by Experts

The correct Answer is:
C
Mn(25) = `[Ar] 3d^(5)4s^(2)`
`Mn^(4+) : [Ar] 3d^(3)`
Number of unpaired electrons , n = 3
Magnetic moment `mu = sqrt(n(n+2))` B.M.
` = sqrt(3(3+2)) = sqrt(15)` B.M.
` = 3.87 BM ~~ 4` B.M.
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