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Methyl cyanide on reduction with sodium ...

Methyl cyanide on reduction with sodium and alcohol gives:

A

Methyl amine

B

Ethyl amine

C

Methyl alcohol

D

Acetic acid.

Text Solution

Verified by Experts

The correct Answer is:
B

`CH_(3)CN+4Hoverset(Na.C_(2)H_(5)OH)rarr underset("Ethyl amine")(CH_(3)CH_(2)NH_(2))`
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