The curve `f(x)=x` at the point with `x = 0`, has
1) vertical tangent
2) horizontal tangent
3) no vertical tangent
4) none of these

The curve y-e^(xy)+x=0 has a vertical tangent at the point :

The curve y-e^(xy)+x=0 has a vertical tangent at the point :

Find number of vertical tangents to the curve y-e^(xy)+x=0

Let C be the curve y^(3) - 3xy + 2 =0 . If H is the set of points on the curve C, where the tangent is horizontal and V is the set of points on the curve C, where the tangent is vertical, then H = … and V = … .

Find the points on the curve y=x^(4)-6x^(2)+4 where the tangent line is horizontal.

Consider the curve represented parametrically by the equation x=t^(3)-4t^(2)-3t and y=2t^(2)+3t-5 where t in R. If H denotes the number of point on the curve where the tangent is horizontal and V the number of point where the tangent is vertical then

If the graph of the function y=f(x) has a unique tangent at point (e^(a),0) (not vertical, non-horizontal) on the graph, then evaluate lim_(xtoe^(a))((1 +9f(x))-"tan"(f(x)))/(2f(x)) .

The point on the curve y^2 + 3x = 12y , when the tangent is vertical, is (are)?