What will be the result of mixing `2kg` of cooper at `100^(@)C` with `0.75` kg of ice at `0^(@)C` (Specific heat capacity of cooper `=378J kg^(-1)K^(-1)` specific heat capacity of water `=4200 J kg^(-1)K^(-1)` and specific latent heat of fusion of ice `=336xx10^(3)Jkg^(-1)`)

Specific heat capacity of water is ____ J kg^(-1) K^(-1) .

What will be the result of mixing 400 g of copper chips at 500^@ C with 500 g of crushed ice at 0^@ C ? Specific heat capacity of copper = 0.42 J g^(-1) K^(-1) , specific latent heat of fusion of ice = 340 J g^(-1) .

Find the result of mixing 1kg of ice at 0^(@)C with 1.5kg of water at 45^(@)C . (Specific latent heat of fusioin of ice =336xx10^(3)Jkg^(-1) )

Calculate the total amount of heat energy required to convert 100 g of ice at -10^@ C completely into water at 100^@ C. Specific heat capacity of ice = 2.1 J g^(-1) K^(-1) , specific heat capacity of water = 4.2 J g^(-1) K^(-1) , specific latent heat of ice = 336 J g^(-1)

Calculate the heat required to convert 3 kg of ice at -12" "^(@)C kept in a calorimeter to steam at 100" "^(@)C at atmospheric pressure. Given specific heat capacity of ice =2100" J kg"^(-1)K^(-1) , specific heat capacity of water =4186" J kg"^(-1)K^(-1) , latent heat of fusionn of ice =3.35xx10^(5)" J kg"^(-1) and latent heat of steam =2.256xx10^(6)" J kg"^(-1) .

A copper calorimeter of mass 100 gm contains 200 gm of a mixture of ice and water. Steam at 100°C under normal pressure is passed into the calorimeter and the temperature of the mixture is allowed to rise to 50°C. If the mass of the calorimeter and its contents is now 330 gm, what was the ratio of ice and water in beginning? Neglect heat losses. Given : Specific heat capacity of copper =0.42xx10^3 J kg^(-1) K^(-1) . Specific heat capacity of water =4.2 xx10^3 J kg^(-1) K^(-1) Specific heat of fusion of ice =3.36xx10^5 J kg^(-1) Latent heat of condensation of steam =22.5 xx 10^5 J kg^(-1)