`sin3 8^(@)+sin2 2^(@)=sin8 2^(@)`

sin1 2^(@)sin4 8^(@)sin5 4^(@)=

(sin2^(@)+sin4^(@)+sin6^(@)+sin8^(@))/(cos1^(@)*cos2^(@)*cos5^(@))=

Find the value of [(sin^2 2 2^(@)+sin^2 6 8^(@))/(cos^2 2 2^(@)+cos^2 6 8^(@))+sin^2 6 3^(@)+cos6 3^(@)sin2 7^(@)]

show that sin ^ (2) 6 ^ (@) + sin ^ (2) 12 ^ (@) + sin ^ (2) 18 ^ (@) + ... + sin ^ (2) 84 ^ (@) + sin ^ (2) 90 ^ (@) = 8

sin ^ (8) A-cos ^ (8) A = (sin ^ (2) A-cos ^ (2) A) (1-2sin ^ (2) A cos ^ (2) A)

The value of 2 sin (pi/8) sin((2pi)/8) sin((3pi)/8) sin ((5pi)/8) sin ((6pi)/8) sin((7pi)/8) is :

Show that: sin^2 pi/8 + sin^2 (3pi)/8+sin^2 (5pi)/8+sin^2 (7pi)/8=2

If cosA+cos^(2)A=1 , then find the value of sin^(12)A+3sin^(10)A+3sin^(8)A+sin^(6)A+sin^(4)A+sin^(2)A .

Show that sin ^(4). (pi)/(8)+ sin ^(4) .(3pi)/(8) sin ^(4). (5pi)/(8)+sin ^(4). (7pi)/(8) =(3)/(2)

sin ^(4) "" (pi)/(8) + sin ^(4) "" (3pi)/(8) + sin ^(4) "" (5pi)/(8) + sin ^(4)"" (7pi)/(8) = (3)/(2).