The acceleration of a particle is `a = - 100x + 50`. It is released from `x = 2`. Here, `a` and `x` are in SI units

The acceleration of a particle moving along x-axis is a=-100x+50 . It is released from x=2 . Here a and x are in S.I units. The motion of particle will be:

The acceleration of a particle moving along x-axis is a=-100x+50 . It is released from x=2 . Here a and x are in S.I units. The motion of particle will be:

The acceleration of a particle moving along x-axis is a=-100x+50 . It is released from x=2 . Here a and x are in S.I units. The motion of particle will be:

The acceleration of a particle moving along x -axis is a= -100x .It is released from rest at x=2. Here a and x are in S.I.units.The minimum time taken by particle to go from x=2 to x=0 is (pi)/(alpha) seconds.Find the value of (alpha)/(4) .

SI unit of acceleration is

SI unit of acceleration is

The potential energy of a particle is given by formula U=100-5x + 100x^(2), where U and 'x' are in SI unit .if mass of particle is 0.1 Kg then find the magnitude of its acceleration

The S.I unit of acceleration is …….