`14xx__=122`

The last two-digits in the multiplication 122xx123xx125xx127xx129 will be

(34.5xx14xx42)div2.8=?

What would be the number in units place of the following expression 122 xx 128 xx 961xx826

Find the value of each of the following by using suitable properties : 8937xx648+8937xx122+8937xx230

If 1.123 xx 3.211 = 3.122+ '_____' then the number in blank space is

Find the sum of the series 2+5+14+41+122+... up to n terms and hence evaluate S_(a).

(0.86 xx 0. 86 xx 0. 86 + 0. 14 xx0.14 xx 0. 14)/(0.86 xx 0.86 - 0. 86 + 0.14 + 0.14 xx 0. 14) is equal to