`x=3costheta-2cos^(3)theta,y=3sintheta-2sin^(3)theta"` then find `dy/dx` at ` "theta=(pi)/(4)`

x=3costheta-2cos^(3)theta, y = 3 sin theta- 2 sin^(3) theta

If x=3cos theta-2cos^(3)theta,y=3sin theta-2sin^(3)theta, then (dy)/(dx) is

If x=3cos theta-cos^(3)theta y=3sin theta-sin^(3)theta find (dy)/(dx)

If x =3 cos theta -2 cos ^(3) theta, y=3sin theta -2 sin ^(3) theta ,then " at " theta =(pi)/(4),(dy)/(dx)

If x=3costheta-cos^3theta y=3sintheta-sin^3theta find dy/dx

(3costheta+cos3theta)/(3sintheta-sin3theta)=

If x+3costheta=2cos^(3)theta,y+2sin^(3)theta=3sintheta," then "(dy)/(dx)=

If x = 3 cos theta - 2 cos^3 theta,y = 3 sin theta - 2 sin^3 theta , then dy/dx is